Your question was –
There are 10 members in a committee. Out of these 10 members, 6 are women and the remaining members are men. But, now the society has fixed the number of female members to 3 and the number of male members to only 1. In how many ways can this combination be formed which results in a committee of exactly 4 members out of which 3 are female and 1 is men from a total of 10 members?

A few days ago I take part an exam where I have faced this GMAT questions and my answers option were –

a. 20
b. 40
c. 60
d. 80
e. None of the above

I have answered as my Correct answer is = d

Because of this following Explanation:

According to the question,
Condition 1:
Total number of members originally = 10 Total number of female members = 6 Total
number of male members = 4
Condition 2:
Total number of members newly = 4 Total number of female members = 3 Total
number of male members = 1
Now, total possible outcomes for 6 females in 3 places = 6*5*4/3*2*1 = 120/6
∴ Total possible outcomes for 6 females in 3 places = 20
Similarly, possible outcomes for 4 males in 1 place = 4/1 = 4.
∴ The total number of combinations is equivalent to the product of the above two results
= 20*4 = 80
Hence, the correct answer is option d.

Hope you have got your answer.
Thanks.